1
MHT CET 2025 22nd April Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$ \int \mathrm{e}^{2 x} \frac{(\sin 2 x \cos 2 x-1)}{\sin ^2 2 x} \mathrm{~d} x= $$

A
$\mathrm{e}^{2 x} \cot (2 x)+\mathrm{c}$, where c is the constant of integration
B
$2 \mathrm{e}^{2 x} \cot (2 x)+\mathrm{c}$, where c is the constant of integration
C
$4 \mathrm{e}^{2 x} \cot (2 x)+\mathrm{c}$, where c is the constant of integration
D
$\frac{1}{2} \mathrm{e}^{2 x} \cot (2 x)+\mathrm{c}$, where c is the constant of integration
2
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$ \int \frac{\sin 2 x \cos 2 x}{\sqrt{9-\cos ^4 2 x}} d x= $$

A
$\frac{1}{4} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+\mathrm{c}$, where c is the constant of integration.
B
$\frac{-1}{4} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+\mathrm{c}$, where c is the constant of integration.
C
$\frac{1}{2} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+\mathrm{c}$, where c is the constant of integration.
D
$\frac{-1}{2} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+\mathrm{c}$, where c is the constant of integration.
3
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$ \int \frac{\cos 2 x-\cos 2 \alpha}{\cos x-\cos \alpha} d x= $$

A
$2 \cos x+2 x \cos \alpha+\mathrm{c}$, where c is the constant of integration.
B
$2 \cos x-2 x \cos \alpha+\mathrm{c}$, where c is the constant of integration.
C
$2 \sin x+2 x \cos \alpha+c$, where $c$ is the constant of integration.
D
$2 \sin x+2 x \sin \alpha+c$, where $c$ is the constant of integration.
4
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\int \frac{2 x^2+3}{\left(x^2-1\right)\left(x^2-4\right)} \mathrm{d} x=\log \left[\left(\frac{x-2}{x+2}\right)^{\mathrm{a}} \cdot\left(\frac{x+1}{x-1}\right)^{\mathrm{b}}\right]+\mathrm{c}$, (where c is the constant of integration) then the value of $a+b$ is equal to

A
$\frac{1}{12}$
B
$\frac{21}{12}$
C
$\frac{-1}{12}$
D
$\frac{-21}{12}$
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