1
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

The unbalanced chemical reactions given in List I show missing reagent or condition (?) which are provided in List II. Match List I with List II and select the correct answer using the code given below the lists :

List I List II
P. $$Pb{O_2} + {H_2}S{O_4}\buildrel ? \over
\longrightarrow PbS{O_4} + {O_2} + Other\,products$$
1. NO
Q. $$N{a_2}{S_2}{O_3} + {H_2}O\buildrel ? \over
\longrightarrow NaHS{O_4} + Other\,products$$
2. $${I_2}$$
R. $${N_2}{H_4}\buildrel ? \over
\longrightarrow {N_2} + Other\,products$$
3. Warm
S. $$Xe{F_2}\buildrel ? \over
\longrightarrow Xe + Other\,products$$
4. $$C{l_2}$$

A
P-4, Q-2, R-3, S-1
B
P-3, Q-2, R-1, S-4
C
P-1, Q-4, R-2, S-3
D
P-3, Q-4, R-2, S-1
2
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using the code given below the lists :

JEE Advanced 2013 Paper 2 Offline Chemistry - Alcohols, Phenols and Ethers Question 23 English

A
P-2, Q-3, R-1, S-4
B
P-3, Q-2, R-1, S-4
C
P-2, Q-3, R-4, S-1
D
P-3, Q-2, R-4, S-1
3
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+4
-1
Let $$S = {S_1} \cap {S_2} \cap {S_3}$$, where $${S_1} = \left\{ {z \in C:\left| z \right| < 4} \right\},{S_2} = \left\{ {z \in C:{\mathop{\rm Im}\nolimits} \left[ {{{z - 1 + \sqrt 3 i} \over {1 - \sqrt 3 i}}} \right] > 0} \right\}$$ and $${S_3} = \left\{ {z \in C:{\mathop{\rm Re}\nolimits} z > 0} \right\}\,$$.

$$\,\mathop {\min }\limits_{z \in S} \left| {1 - 3i - z} \right| = $$

A
$${{2 - \sqrt 3 } \over 2}$$
B
$${{2 + \sqrt 3 } \over 2}$$
C
$${{3 - \sqrt 3 } \over 2}$$
D
$${{3 + \sqrt 3 } \over 2}$$
4
JEE Advanced 2013 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1

Let $\omega=\frac{\sqrt{3}+i}{2}$ and $P=\left\{\omega^n: n=1,2,3, \ldots\right\}$. Further

$\mathrm{H}_1=\left\{z \in \mathrm{C}: \operatorname{Re} z<\frac{1}{2}\right\}$ and

$\mathrm{H}_2=\left\{z \in \mathrm{C}: \operatorname{Re} z<\frac{-1}{2}\right\}$, where C is the

set of all complex numbers. If $z_1 \in \mathrm{P} \cap \mathrm{H}_1, z_2 \in$ $\mathrm{P} \cap \mathrm{H}_2$ and O

represents the origin, then $\angle z_1 \mathrm{O} z_2=$

A
$${\pi \over 2}$$
B
$${\pi \over 6}\,$$
C
$${{2\pi } \over 3}$$
D
$${{5\pi } \over 6}$$

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