1
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

The unbalanced chemical reactions given in List I show missing reagent or condition (?) which are provided in List II. Match List I with List II and select the correct answer using the code given below the lists :

List I List II
P. $$Pb{O_2} + {H_2}S{O_4}\buildrel ? \over
\longrightarrow PbS{O_4} + {O_2} + Other\,products$$
1. NO
Q. $$N{a_2}{S_2}{O_3} + {H_2}O\buildrel ? \over
\longrightarrow NaHS{O_4} + Other\,products$$
2. $${I_2}$$
R. $${N_2}{H_4}\buildrel ? \over
\longrightarrow {N_2} + Other\,products$$
3. Warm
S. $$Xe{F_2}\buildrel ? \over
\longrightarrow Xe + Other\,products$$
4. $$C{l_2}$$

A
P-4, Q-2, R-3, S-1
B
P-3, Q-2, R-1, S-4
C
P-1, Q-4, R-2, S-3
D
P-3, Q-4, R-2, S-1
2
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using the code given below the lists :

JEE Advanced 2013 Paper 2 Offline Chemistry - Alcohols, Phenols and Ethers Question 12 English

A
P-2, Q-3, R-1, S-4
B
P-3, Q-2, R-1, S-4
C
P-2, Q-3, R-4, S-1
D
P-3, Q-2, R-4, S-1
3
JEE Advanced 2013 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
Let $$w = {{\sqrt 3 + i} \over 2}$$ and P = { $${w^n}$$ : n = 1, 2, 3, ...}. Further JEE Advanced 2013 Paper 2 Offline Mathematics - Complex Numbers Question 48 English 1 and JEE Advanced 2013 Paper 2 Offline Mathematics - Complex Numbers Question 48 English 2, where is the set of all complex numbers. If $${z_1} \in P \cap {H_1},\,{z_2} \in \,P \cap {H_2}$$ and 0 represents the origin, then $$\angle \,{z_1}\,o{z_2} = $$
A
$${\pi \over 2}$$
B
$${\pi \over 6}\,$$
C
$${{2\pi } \over 3}$$
D
$${{5\pi } \over 6}$$
4
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+4
-1
Let $$S = {S_1} \cap {S_2} \cap {S_3}$$, where $${S_1} = \left\{ {z \in C:\left| z \right| < 4} \right\},{S_2} = \left\{ {z \in C:{\mathop{\rm Im}\nolimits} \left[ {{{z - 1 + \sqrt 3 i} \over {1 - \sqrt 3 i}}} \right] > 0} \right\}$$ and $${S_3} = \left\{ {z \in C:{\mathop{\rm Re}\nolimits} z > 0} \right\}\,$$.

Area of S =

A
$${{10\pi } \over 3}$$
B
$${{20\pi } \over 3}$$
C
$${{16\pi } \over 3}$$
D
$${{32\pi } \over 3}$$
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