1
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

Find the equation of the common tangent in the first quadrant to the circle $$x^{2}+y^{2}=16$$ and the ellipse $$\frac{x^{2}}{25}+\frac{y^{2}}{4}=1$$. Also find the length of the intercept of the tangent between the coordinate axes.

A
$$\frac{14}{\sqrt5}$$
B
$$\frac{5}{\sqrt3}$$
C
$$\frac{14}{\sqrt3}$$
D
$$\frac{15}{\sqrt3}$$
2
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

If length of tangent at any point on the curve $$y = f(x)$$ intercepted between the point and the X-axis is of length 1. Find the equation of the curve.

A
$$\sqrt{1-y^{2}}-\frac{1}{2} \log \left|\frac{1+\sqrt{1-y^{2}}}{1-\sqrt{1-y^{2}}}\right|= \pm x+c$$
B
$$\sqrt{1-y^{2}}- \log \left|\frac{1+\sqrt{1-y^{2}}}{1-\sqrt{1-y^{2}}}\right|= \pm x+c$$
C
$$\sqrt{1-y^{2}}+\frac{1}{2} \log \left|\frac{1+\sqrt{1-y^{2}}}{1-\sqrt{1-y^{2}}}\right|= \pm x+c$$
D
$$\sqrt{1-y^{2}}-\frac{1}{2} \log \left|\frac{1+\sqrt{1-y^{2}}}{1-\sqrt{1-y^{2}}}\right|= \pm 5x+c$$
3
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

Find the area bounded by the curves $$x^{2}=y, x^{2}=-y$$ and $$y^{2}=4 x-3$$.

A
$$\frac{1}{3}$$
B
$$\frac{1}{5}$$
C
$$\frac{2}{3}$$
D
$$\frac{1}{7}$$
4
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

If one of the vertices of the square circumscribing the circle $$|z-1|=\sqrt{2}$$ is $$(2+\sqrt{3 i})$$. Find the other vertices of square.

A
$$\left( {1 - 2\sqrt 3 } \right) + i,\left( {1 + \sqrt 3 } \right) - i, - \sqrt 3 i$$
B
$$\left( {1 - \sqrt 3 } \right) + i,\left( {2 + \sqrt 3 } \right) - i, - i$$
C
$$\left( {1 - \sqrt 3 } \right) + i,\left( {1 + 2\sqrt 3 } \right) - i, - \sqrt 5 i$$
D
$$\left( {1 - \sqrt 3 } \right) + i,\left( {1 + \sqrt 3 } \right) - i, - \sqrt 3 i$$

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