1
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

Evatuate:

$$\int_\limits{0}^{\pi} e^{|\cos x|}\left[2 \sin \left(\frac{1}{2} \cos x\right)+3 \cos \left(\frac{1}{2} \cos x\right)\right] \sin x ~d x$$

A
$${e \over 5}\left[ {\cos \left( {{1 \over 2}} \right) + \left( {{1 \over 2}} \right)\sin \left( {{1 \over 2}} \right) - 1} \right]$$
B
$$24{e \over 5}\left[ {\cos \left( {{1 \over 2}} \right) + \left( {{1 \over 2}} \right)\sin \left( {{1 \over 2}} \right) - 1} \right]$$
C
$$12{e \over 5}\left[ {\cos \left( {{1 \over 2}} \right) + \left( {{1 \over 2}} \right)\sin \left( {{1 \over 2}} \right) - 1} \right]$$
D
$$5{e \over 5}\left[ {\cos \left( {{1 \over 2}} \right) + \left( {{1 \over 2}} \right)\sin \left( {{1 \over 2}} \right) - 1} \right]$$
2
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

Incident ray is along the unit vector $$\hat{v}$$ and the reflected ray is along the unit vector $$\widehat{w}$$. The normal is along unit vector $$\hat{a}$$ outwards. Express $$\hat{w}$$, in terms of $$\hat{a}$$ and $$\hat{v}$$.

A
$$\widehat{w}=\hat{v}-2(\hat{a} \cdot \hat{v}) \cdot \hat{a}$$
B
$$\widehat{w}=\hat{v}+2(\hat{a} \cdot \hat{v}) \cdot \hat{a}$$
C
$$\widehat{w}=\hat{v}-3(\hat{a} \cdot \hat{v}) \cdot \hat{a}$$
D
$$\widehat{w}=5\hat{v}+3(\hat{a} \cdot \hat{v}) \cdot \hat{a}$$
3
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

Tangents are drawn from any point on the hyperbola $$\frac{x^{2}}{9}-\frac{y^{2}}{4}=1$$ to the circle $$x^{2}+y^{2}=9$$. Find the locus of mid-point of the chord of contact.

A
$${{{x^2}} \over 4} + {{{y^2}} \over 9} = {{{{({x^2} + {y^2})}^2}} \over {81}}$$
B
$${{{x^2}} \over 4} - {{{y^2}} \over 9} = {{{{({x^2} + {y^2})}^2}} \over {81}}$$
C
$${{{x^2}} \over 9} + {{{y^2}} \over 4} = {{{{({x^2} + {y^2})}^2}} \over {81}}$$
D
$${{{x^2}} \over 9} - {{{y^2}} \over 4} = {{{{({x^2} + {y^2})}^2}} \over {81}}$$
4
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

Find the equation of the common tangent in the first quadrant to the circle $$x^{2}+y^{2}=16$$ and the ellipse $$\frac{x^{2}}{25}+\frac{y^{2}}{4}=1$$. Also find the length of the intercept of the tangent between the coordinate axes.

A
$$\frac{14}{\sqrt5}$$
B
$$\frac{5}{\sqrt3}$$
C
$$\frac{14}{\sqrt3}$$
D
$$\frac{15}{\sqrt3}$$

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