IIT-JEE 2005 Mains | JEE Advanced Year Wise Previous Years Questions

IIT-JEE 2005 Mains

MCQ (Single Correct Answer)

-1

A transverse harmonic disturbance is produced in a string. The maximum transverse velocity is 3 m/s and the maximum transverse acceleration is 90 m/s$$^2$$ . If the wave velocity is 20 m/s, then find the waveform.

$$[y=(0.45) \sin \{[(30) t \pm(1.5) x] \pm \phi\}]$$

$$[y=(0.5) \sin \{[(50) t \pm(2.5) x] \pm \phi\}]$$

$$[y=(0.1) \sin \{[(30) t \pm(1.5) x] \pm \phi\}]$$

$$[y=(0.2) \sin \{[(60) t \pm(1.5) x] \pm \phi\}]$$

IIT-JEE 2005 Mains

MCQ (Single Correct Answer)

-1

A cylinder of mass m and radius R rolls down on an inclined plane of inclination $$\theta$$. Calculate the linear acceleration of axis of cylinder.

$$a=\frac{2}{3} g \sin \theta$$

$$a= g \sin \theta$$

$$a=\frac{5}{3} g \sin \theta$$

$$a=\frac{7}{3} g \sin \theta$$

IIT-JEE 2005 Mains

MCQ (Single Correct Answer)

-1

A long solenoid of radius a and number of turns per unit length $$n$$ is enclosed by cylindrical shell of radius R, thickness $$d$$ $$(d < < R)$$ and length L. A variable current $$\mathrm{I}=\mathrm{I}_{0} \sin \omega t$$ flows through the coil. If the resistivity of the material of cylindrical shell is $$\mathrm{P}$$, find the induced current in the shell.

IIT-JEE 2005 Mains Physics - Electromagnetic Induction Question 10 English

$$\mathrm{I}=\frac{\left(\mu_{0} \mathrm{~L} d n a^{2} \mathrm{I}_{0} \omega \cos \omega t\right)}{\rho \mathrm{R}}$$

$$\mathrm{I}=\frac{\left(3\mu_{0} \mathrm{~L} d n a^{2} \mathrm{I}_{0} \omega \cos \omega t\right)}{2 \rho \mathrm{R}}$$

$$\mathrm{I}=\frac{\left(\mu_{0} \mathrm{~L} d n a^{2} \mathrm{I}_{0} \omega \cos \omega t\right)}{2 \rho \mathrm{R}}$$

$$\mathrm{I}=\frac{3\left(\mu_{0} \mathrm{~L} d n a^{2} \mathrm{I}_{0} \omega \cos \omega t\right)}{ \rho \mathrm{R}}$$

IIT-JEE 2005 Mains

MCQ (Single Correct Answer)

-1

Two identical ladders, each of mass M and length L are resting on the rough horizontal surface as shown in the figure. A block of mass $$m$$ hangs from P. If the system is in equilibrium, find the magnitude and the direction of frictional force at A and B.

IIT-JEE 2005 Mains Physics - Rotational Motion Question 17 English

$$f=\left[\frac{\mathbf{M}+m}{2}\right] g \cot \theta$$

$$f=\left[\frac{\mathbf{M}+m}{3}\right] g \cot \theta$$

$$f=\left[\frac{\mathbf{M}+m}{2}\right] 5g \cot \theta$$

$$f=\left[\frac{\mathbf{M}+m}{4}\right] g \cot \theta$$

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