1
GATE ECE 2006
MCQ (Single Correct Answer)
+2
-0.6
A signal m(t) with bandwidth 500 Hz is first multiplied by a signal g(t) where $$g(t)\, = \,\,\sum\limits_{k = - \infty }^\infty {{{( - 10)}^k}\,\delta (t - 0.5x{{10}^{ - 4}}k)} $$
The resulting signal is then passed through an ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would be
A
$${\delta (t)}$$
B
m(t)
C
0
D
m(t) $${\delta (t)}$$
2
GATE ECE 2006
MCQ (Single Correct Answer)
+2
-0.6
The minimum sampling frequency (in samples /sec) required to reconstruct the following signal from its samples without distortion $$x(t) = 5{\left( {{{\sin \,\,2\,\pi \,1000\,t)} \over {\pi \,t}}} \right)^3} + 7{\left( {{{\sin \,\,2\,\pi \,1000\,t} \over {\pi \,t}}} \right)^2}$$

would be

A
$$2 \times {10^3}$$
B
$$4 \times {10^3}$$
C
$$6 \times {10^3}$$
D
$$8 \times {10^3}$$
3
GATE ECE 2006
MCQ (Single Correct Answer)
+1
-0.3
A low-pass filter having a frequency response $$H(j\omega )$$ = $$A(\omega ){e^{j\Phi (\omega )}}$$, does not product any phase distortion if
A
$$A(\omega ) = C{\omega ^2},\,\,\phi (\omega ) = K{\omega ^3}$$
B
$$A(\omega ) = C{\omega ^2},\,\,\phi (\omega ) = K\omega $$
C
$$A(\omega ) = C\omega ,\,\,\phi (\omega ) = K{\omega ^2}$$
D
$$A(\omega ) = C,\,\,\phi (\omega ) = K{\omega ^{ - 1}}$$
4
GATE ECE 2006
MCQ (Single Correct Answer)
+1
-0.3
In the system shown below,
x(t) = (sint)u(t). In steady-state, the response y(t) will be GATE ECE 2006 Signals and Systems - Transmission of Signal Through Continuous Time LTI Systems Question 31 English
A
$${1 \over {\sqrt 2 }}\sin \left( {t - {\pi \over 4}} \right)$$
B
$${1 \over {\sqrt 2 }}\sin \left( {t + {\pi \over 4}} \right)$$
C
$${1 \over {\sqrt 2 }}{e^{ - t}}\sin (t)$$
D
$$\sin (t) - \cos (t)$$
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