MHT CET 2026 20th April Morning Shift | Electrostatics Question 6 | Physics

Two point charges $q_1$ and $q_2$ are '$l$' distance apart. If one of the charges is doubled and the distance between them is halved. The magnitude of the force becomes 'n' times, where 'n' is

$2$

$4$

$8$

$16$

MHT CET 2026 19th April Evening Shift

MCQ (Single Correct Answer)

-0

An uniformly charged thin spherical shell of radius 'R' has uniform surface charge density '$\sigma$'. It is made of two hemispherical identical shells held together by pressing them with force 'F' as shown. F is proportional to
[$\epsilon_0$ = permittivity of free space]

$\dfrac{1}{\epsilon_0}\,\dfrac{\sigma^2}{R^2}$

$\dfrac{1}{\epsilon_0}\,\dfrac{\sigma^2}{R}$

$\dfrac{1}{\epsilon_0}\,\sigma^2 R^2$

$\dfrac{1}{\epsilon_0}\,\sigma^2 R$

MHT CET 2026 19th April Evening Shift

MCQ (Single Correct Answer)

-0

Two equal positive charges each of value 'q' are placed at points A and B, where $AB = 3x$. A third charge $-3q$ is placed at point C at a distance $x$ from A on AB. The potential energy of the system is nearly ($\epsilon_0$ = permittivity of free space)

$\dfrac{q^2}{4\pi\epsilon_0 x}$

$\dfrac{-2q^2}{4\pi\epsilon_0 x}$

$\dfrac{3q^2}{4\pi\epsilon_0 x}$

$\dfrac{-4q^2}{4\pi\epsilon_0 x}$

MHT CET 2026 19th April Evening Shift

MCQ (Single Correct Answer)

-0

A particle of mass 'm' and charge 'q', initially at rest, is accelerated by a uniform electric field 'E' through a distance 'D' and is then allowed to approach a fixed static charge 'Q' of the same sign. The distance of the closest approach of the charge q is
[ $\epsilon_0$ = permittivity of free space ]

$Q / 4\pi\epsilon_0 D$

$Q / 4\pi\epsilon_0 ED$

$Q / 2\pi\epsilon_0 D^2$

$Q / 4\pi\epsilon_0 E$

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