MHT CET 2026 13th April Morning Shift | Fluid Mechanics Question 41 | Physics

Three liquids have same surface tension and have densities $\rho_1, \rho_2$ and $\rho_3$ $(\rho_1 > \rho_2 > \rho_3)$. In three identical capillaries rise of liquid is same. The corresponding angles of contact $\theta_1, \theta_2$ and $\theta_3$ are related as

$\theta_1 > \theta_2 > \theta_3$

$\theta_1 < \theta_2 < \theta_3$

$\theta_1 = \theta_2 = \theta_3$

$\theta_1 > \theta_2 < \theta_3$

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

The work done in splitting a water drop of radius 'R' into 64 droplets is (T is the surface tension of water)

$8\pi R^2 T$

$12\pi R^2 T$

$4\pi R^2 T$

$16\pi R^2 T$

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

A liquid drop having surface energy E is sprayed into $512$ droplets of the same size. Then the final surface energy is

$4E$

$8E$

$2E$

$E$

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

In a capillary tube of radius 'R', a straight thin metal wire of radius 'r' is inserted symmetrically and one end of the combination is dipped vertically in water such that lower end of the capillary and thin wire are at same level. If 'T' is the surface tension of water and '$\rho$' is the density of water then the rise of water in the capillary is

$\dfrac{T}{(R-r)\rho g}$

$\dfrac{2T}{(R-r)\rho g}$

$\dfrac{4T}{(R+r)\rho g}$

$\dfrac{T}{(R+r)\rho g}$

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