MHT CET 2026 16th April Evening Shift | Fluid Mechanics Question 25 | Physics

Under isothermal condition, two soap bubbles of radii $r_1$ and $r_2$ combine to form a single soap bubble of radius R. The surface tension of the soap solution is (P = outside pressure)

$\dfrac{P(R^3 - r_1^3 - r_2^3)}{4(r_1^2 + r_2^2 - R^2)}$

$\dfrac{P(R^3 + r_1^3 + r_2^3)}{2(r_1^2 - r_2^2 + R^2)}$

$\dfrac{P(r_1^3 - r_2^3 - R^3)}{(R^2 + r^2 + r^2)}$

$\dfrac{P(R^3 - r_1^3 + r_2^3)}{2(r_1^2 + r_2^2 - R^2)}$

MHT CET 2026 16th April Evening Shift

MCQ (Single Correct Answer)

-0

A horizontal pipe carries water in a streamline flow. At point along the pipe, where the cross-sectional area is $A_1$, the velocity of water is $V_1$ and the pressure is $P_1$. What is the pressure of water at another point where the cross-sectional area is $A_2$?

$P_1 - \dfrac{\varrho V_2^2}{2A_1^2}(A_2^2 - A_1^2)$

$P_1 + \dfrac{\varrho V_1^2}{2A_2^2}(A_2^2 - A_1^2)$

$P_1\varrho V_1^2(A_1^2 - A_2^2)$

$P/\varrho V_1^2 A_2^2$

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

-0

A closed pipe containing liquid showed a pressure $P_1$ by gauge. When the valve was opened, pressure was reduced to $P_2$. The speed of water flowing out of the pipe is ($\varrho$=density of water)

$\left[\dfrac{(P_1 - P_2)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{2(P_1 - P_2)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{(P_2 - P_1)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{2(P_2 - P_1)}{\varrho}\right]^{\frac{1}{2}}$

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