1
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A glass tube of uniform cross-section is connected to a tap with a rubber tube. The tap is opened slowly. Initially the flow of water in the tube is streamline. The speed of flow of water to convert it into a turbulent flow is [radius of tube $$=1 \mathrm{~cm}, \eta=1 \times 10^{-3} \frac{\mathrm{Ns}}{\mathrm{m}^2}, R_n=2500$$ and density of water $$=10^3 \mathrm{~kg} / \mathrm{m}^3$$]

A
0.15 m/s
B
0.125 m/s
C
0.3 m/s
D
0.2 m/s
2
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A thin metal disc of radius 'r' floats on water surface and bends the surface downwards along the perimeter making an angle '$$\theta$$' with the vertical edge of the dsic. If the weight of water displaced by the disc is '$$\mathrm{W}$$', the weight of the metal disc is [T = surface tension of water]

A
$$2 \pi \mathrm{r} \cos \theta+W$$
B
$$\mathrm{W}-2 \pi \mathrm{T} \cos \theta$$
C
$$\mathrm{2 \pi r T+W}$$
D
$$2 \pi \mathrm{T} \cos \theta-\mathrm{W}$$
3
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The work done in blowing a soap bubble of volume '$$\mathrm{V}$$' is '$$\mathrm{W}$$'. The work required to blow a soap bubble of volume '$$2 \mathrm{~V}$$' is [$$\mathrm{T}=$$ surface tension of soap solution]

A
$$2^{2 / 3} \mathrm{~W}$$
B
$$2 \mathrm{~W}$$
C
$$\mathrm{W}$$
D
$$2^{1 / 3} \mathrm{~W}$$
4
MHT CET 2021 23rd September Evening Shift
MCQ (Single Correct Answer)
+1
-0

A glass rod of radius '$$r_1$$' is inserted symmetrically into a vertical capillary tube of radius '$$r_2$$' ($$r_1 < \mathrm{r}_2$$) such that their lower ends are at same level. The arrangement is dipped in water. The height to which water will rise into the tube will be ($$\rho=$$ density of water, T = surface tension in water, g = acceleration due to gravity)

A
$$\frac{2 T}{\left(r_2-r_1\right) \rho g}$$
B
$$\frac{T}{\left(r_2^2-r_1^2\right) \rho g}$$
C
$$\frac{T}{\left(r_2-r_1\right) \rho g}$$
D
$$\frac{2 \mathrm{~T}}{\left(\mathrm{r}_2^2-\mathrm{r}_1^2\right) \rho g}$$
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