MHT CET 2024 4th May Evening Shift | Fluid Mechanics Question 30 | Physics

A hemispherical portion of radius ' $R$ ' is removed from the bottom of a cylinder of radius ' R '. The volume of the remaining cylinder is ' V ' and its mass is ' M '. It is suspended by a string in a liquid of density ' $\rho$ ', where it stays vertical. The upper surface of the cylinder is at a depth ' $h$ ' below the liquid surface. The force on the bottom of the liquid is

$\mathrm{Mg}-\mathrm{V} \rho g$

$\mathrm{Mg}+\pi \mathrm{R}^2 \mathrm{~h} \rho g$

$ \mathrm{pg}\left(\mathrm{V}+\pi \mathrm{r}^2 \mathrm{~h}\right)$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

A water film is formed between two parallel wires of 10 cm length. The distance of 0.5 cm between the wires is increased by 1 mm . The work done in the process is (surface tension of water $=72 \mathrm{~N} / \mathrm{m}$)

$2.88 \times 10^{-2} \mathrm{~J}$

$7.2 \times 10^{-2} \mathrm{~J}$

$1.44 \times 10^{-2} \mathrm{~J}$

$3.6 \times 10^{-2} \mathrm{~J}$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

Identify the correct figure which shows the relation between the height of water column in a capillary tube and the capillary radius.

MHT CET 2024 4th May Evening Shift Physics - Fluid Mechanics Question 30 English

(B)

(D)

(A)

(C)

MHT CET 2024 4th May Morning Shift

MCQ (Single Correct Answer)

-0

Water rises up to height ' $X$ ' in a capillary tube immersed vertically in water. When the whole arrangement is taken to a depth ' d ' in a mine, the water level rises up to height ' $Y$ '. If ' $R$ ' is the radius of earth then the ratio $\frac{Y}{X}$ is

$\left(1-\frac{d}{R}\right)^{-1}$

$\left(1-\frac{d}{R}\right)$

$\left(1+\frac{d}{R}\right)^{-1}$

$\left(1+\frac{d}{R}\right)$

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