1
MHT CET 2021 21th September Evening Shift
+1
-0

Under isothermal conditions, two soap bubbles of radii '$$r_1$$' and '$$r_2$$' combine to form a single soap bubble of radius '$$R$$'. The surface tension of soap solution is ( $$P=$$ outside pressure)

A
$$\frac{P\left(R^3+r_1^3+r_2^3\right)}{4\left(r_1^2-r_2^2+R^2\right)}$$
B
$$\frac{P^2+r_1^2+r_2^2}{4\left(r_1^2+r_2^2+R^2\right)}$$
C
$$\frac{P\left(R^3-r_1^3-r_2^3\right)}{4\left(r_1^2+r_2^2-R^2\right)}$$
D
$$\frac{P\left(R^2-r_1^2-r_2^2\right)}{4\left(r_1^3+r_2^3-R^3\right)}$$
2
MHT CET 2021 21th September Evening Shift
+1
-0

In a capillary tube having area of cross-section A, water rises to a height 'h'. If cross-sectional area is reduced to $$\frac{A}{9}$$, the rise of water in the capillary tube is

A
3h
B
9h
C
h
D
6h
3
MHT CET 2021 21th September Evening Shift
+1
-0

Water rises upto a height $$10 \mathrm{~cm}$$ in a capillary tube. It will rise to a height which is much more than $$10 \mathrm{~cm}$$ in a very long capillary tube if the apparatus is kept.

A
on the surface of the moon.
B
at the north pole.
C
in a lift moving up with an acceleration.
D
on the equator.
4
MHT CET 2021 21th September Evening Shift
+1
-0

A big water drop is divided into 8 equal droplets. $$\Delta \mathrm{P}_{\mathrm{s}}$$ and $$\Delta \mathrm{P}_{\mathrm{B}}$$ be the excess pressure inside a smaller and bigger drop respectively. The relation between $$\Delta \mathrm{P}_{\mathrm{s}}$$ and $$\Delta \mathrm{P}_{\mathrm{B}}$$ is

A
$$\Delta P_B=\Delta P_S$$
B
$$\Delta \mathrm{P}_{\mathrm{B}}=\frac{1}{2} \Delta \mathrm{P}_{\mathrm{S}}$$
C
$$\Delta P_B=\frac{1}{4} \Delta P_S$$
D
$$\Delta P_B=2 \Delta P_S$$
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