1
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The negation of the converse of $p \vee q$ is
A
$\sim p \vee q$
B
$p \wedge q$
C
$p \vee \sim q$
D
$\sim p \wedge \sim q$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Which of the following statements is/are False?
$S_1 : \exists\, n \in N$, such that $n^2 + n + 2$ is divisible by 4.
$S_2 : \exists\, x \in N$, such that $x - 17 < 20$.
$S_3 : \forall\, n \in N, \quad x^2 + 3x - 10 = 0$.
$S_4 : \forall\, n \in N, \quad n^2 \geq 1$.
A
$S_1$ and $S_2$.
B
$S_1$ and $S_3$.
C
Only $S_3$.
D
$S_2$ and $S_4$.
3
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The negation of $(p \wedge q) \rightarrow ((p \vee r) \rightarrow\, \sim q)$ is equivalent to ...
A
$p \wedge q$
B
$p \wedge\, \sim r$
C
$q \wedge (p \vee r)$
D
$\sim p \wedge\, \sim q$
4
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The statement pattern $[(p \wedge q) \rightarrow (\sim p \vee r)] \vee [(\sim p \vee r) \rightarrow (p \wedge q)]$ is
A
a contradiction
B
a tautology
C
equivalent to $(p \wedge q) \vee r$.
D
equivalent to $(p \vee q)$ .

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