1
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If the statement $$\mathrm{p} \leftrightarrow(\mathrm{q} \rightarrow \mathrm{p})$$ is false, then true statement/statement pattern is

A
$$\mathrm{p}$$
B
$$\mathrm{p} \rightarrow(\mathrm{p} \vee \sim \mathrm{q})$$
C
$$\mathrm{p} \wedge(\sim \mathrm{p} \wedge \mathrm{q})$$
D
$$(p \vee \sim q) \rightarrow p$$
2
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The statement $$[\mathrm{p} \wedge(\mathrm{q} \vee \mathrm{r})] \vee[\sim \mathrm{r} \wedge \sim \mathrm{q} \wedge \mathrm{p}]$$ is equivalent to

A
$$\sim \mathrm{r}$$
B
$$\mathrm{p}$$
C
$$\sim \mathrm{q}$$
D
$$\mathrm{q}$$
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The negation of the statement

"The number is an odd number if and only if it is divisible by 3."

A
The number is an odd number but not divisible by 3 or the number is divisible by 3 but not odd.
B
The number is not an odd number iff it is not divisible by 3.
C
The number is not an odd number but it is divisible by 3.
D
The number is not an odd number or is not divisible by 3 but the number is divisible by 3 or odd.
4
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The statement $$[(p \rightarrow q) \wedge \sim q] \rightarrow r$$ is tautology, when $$r$$ is equivalent to

A
$$\mathrm{p} \wedge \sim \mathrm{q}$$
B
$$q \vee p$$
C
$$\mathrm{p} \wedge \mathrm{q}$$
D
$$\sim q$$
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