MHT CET 2023 12th May Morning Shift | Circular Motion Question 8 | Physics

Two particles having mass '$$M$$' and '$$m$$' are moving in a circular path with radius '$$R$$' and '$$r$$' respectively. The time period for both the particles is same. The ratio of angular velocity of the first particle to the second particle will be

1 : 1

1 : 2

2 : 3

3 : 4

MHT CET 2023 11th May Evening Shift

MCQ (Single Correct Answer)

-0

In a conical pendulum the bob of mass '$$\mathrm{m}$$' moves in a horizontal circle of radius '$$r$$' with uniform speed '$$\mathrm{V}$$'. The string of length '$$\mathrm{L}$$' describes a cone of semi vertical angle '$$\theta$$'. The centripetal force acting on the bob is ( $$\mathrm{g}=$$ acceleration due to gravity)

$$\frac{\mathrm{mgr}}{\sqrt{\mathrm{L}^2-\mathrm{r}^2}}$$

$$\frac{\mathrm{mgr}}{\left(\mathrm{L}^2-\mathrm{r}^2\right)}$$

$$\frac{\sqrt{\mathrm{L}^2-\mathrm{r}^2}}{\mathrm{mgL}}$$

$$\frac{\mathrm{mgL}}{\sqrt{\mathrm{L}^2-\mathrm{r}^2}}$$

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

A ball of mass '$$\mathrm{m}$$' is attached to the free end of a string of length '$$l$$'. The ball is moving in horizontal circular path about the vertical axis as shown in the diagram.

The angular velocity '$$\omega$$' of the ball will be [ $$\mathrm{T}=$$ Tension in the string.]

MHT CET 2023 11th May Morning Shift Physics - Circular Motion Question 16 English

$$\sqrt{\frac{\mathrm{T} l}{\mathrm{~m}}}$$

$$\sqrt{\frac{\mathrm{Tm}}{l}}$$

$$\sqrt{\frac{\mathrm{m} l}{\mathrm{~T}}}$$

$$\sqrt{\frac{\mathrm{T}}{\mathrm{ml} l}}$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

A particle performing uniform circular motion of radius $$\frac{\pi}{2} \mathrm{~m}$$ makes '$$\mathrm{x}$$' revolutions in time '$$t$$'. Its tangential velocity is

$$\frac{\pi \mathrm{x}}{\mathrm{t}}$$

$$\frac{\pi x^2}{t}$$

$$\frac{\pi^2 x^2}{t}$$

$$\frac{\pi^2 \mathrm{x}}{\mathrm{t}}$$

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