1
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The statement $$[(p \rightarrow q) \wedge \sim q] \rightarrow r$$ is tautology, when $$r$$ is equivalent to

A
$$\mathrm{p} \wedge \sim \mathrm{q}$$
B
$$q \vee p$$
C
$$\mathrm{p} \wedge \mathrm{q}$$
D
$$\sim q$$
2
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$q$$ is false and $$p \wedge q \leftrightarrow r$$ is true, then ............ is a tautology.

A
$$p \vee r$$
B
$$(p \wedge r) \rightarrow p \vee r$$
C
$$(p \vee r) \rightarrow p \wedge r$$
D
$$p \wedge r$$
3
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Negation of contrapositive of statement pattern $$(p \vee \sim q) \rightarrow(p \wedge \sim q)$$ is

A
$$(\sim p \wedge q) \vee(p \wedge \sim q)$$
B
$$(\sim p \vee q) \wedge(p \vee \sim q)$$
C
$$(p \wedge \sim q) \vee(\sim p \wedge \sim q)$$
D
$$(\sim p \vee \sim q) \wedge(p \vee q)$$
4
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The expression $$(p \wedge \sim q) \vee q \vee(\sim p \wedge q)$$ is equivalent to

A
$$\sim \mathrm{p} \vee \mathrm{q}$$
B
$$p \wedge q$$
C
$$\mathrm{p} \vee \mathrm{q}$$
D
$$p \vee \sim q$$
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