1
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The statement $$[\mathrm{p} \wedge(\mathrm{q} \vee \mathrm{r})] \vee[\sim \mathrm{r} \wedge \sim \mathrm{q} \wedge \mathrm{p}]$$ is equivalent to

A
$$\sim \mathrm{r}$$
B
$$\mathrm{p}$$
C
$$\sim \mathrm{q}$$
D
$$\mathrm{q}$$
2
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The negation of the statement

"The number is an odd number if and only if it is divisible by 3."

A
The number is an odd number but not divisible by 3 or the number is divisible by 3 but not odd.
B
The number is not an odd number iff it is not divisible by 3.
C
The number is not an odd number but it is divisible by 3.
D
The number is not an odd number or is not divisible by 3 but the number is divisible by 3 or odd.
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The statement $$[(p \rightarrow q) \wedge \sim q] \rightarrow r$$ is tautology, when $$r$$ is equivalent to

A
$$\mathrm{p} \wedge \sim \mathrm{q}$$
B
$$q \vee p$$
C
$$\mathrm{p} \wedge \mathrm{q}$$
D
$$\sim q$$
4
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$q$$ is false and $$p \wedge q \leftrightarrow r$$ is true, then ............ is a tautology.

A
$$p \vee r$$
B
$$(p \wedge r) \rightarrow p \vee r$$
C
$$(p \vee r) \rightarrow p \wedge r$$
D
$$p \wedge r$$
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