MHT CET 2020 16th October Evening Shift | Vector Algebra Question 4 | Physics

The resultant of two vector $$\mathbf{A}$$ and $$\mathbf{B}$$ is $$\mathbf{C}$$. If the magnitude of $$\mathbf{B}$$ is doubled, the new resultant vector becomes perpendicular to A. Then, the magnitude of $$\mathbf{C}$$ is

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

Two vectors of same magnitude have a resultant equal to either of the two vectors. The angle between two vectors is

$$\cos ^{-1}(-0.5)$$

$$\cos ^{-1}(-0.4)$$

$$\cos ^{-1}(-0.3)$$

$$\cos ^{-1}(-0.6)$$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

The vectors $(\mathbf{A}+\mathbf{B})$ and $(\mathbf{A}-\mathbf{B})$ are at right. angles to each other. This is possible under the condition

$|A|=|B|$

$A \cdot B=0$

$A \cdot B=1$

$A \times B=0$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

A vector $P$ has $X$ and $Y$ components of magnitude 2 units and 4 units respectively. A vector $Q$ along negative $X$-axis has magnitude 6 units. The vector $(\mathbf{Q}-\mathbf{P})$ will be

$4(2 \hat{i}-\hat{j})$

$-4(2 \hat{\mathbf{i}}-\hat{\mathrm{j}})$

$4(2 \hat{i}+\hat{j})$

$-4(2 \hat{i}+\hat{j})$

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