MHT CET 2024 9th May Morning Shift | Moving Charges and Magnetism Question 26 | Physics

The magnetic field intensity inside current carrying solenoid is $\mathrm{H}=2.4 \times 10^3 \mathrm{~A} / \mathrm{m}$. If length and number of turns of a solenoid is 15 cm and 60 turns respectively. The current flowing in the solenoid is

4 A

6 A

0.6 A

60 A

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

A particle carrying a charge equal to 100 times the charge on an electron is rotating one rotation per second in a circular path of radius 0.8 m . The value of magnetic field produced at the centre will be ( $\mu_0=$ permeability of vacuum)

$\frac{10^{-7}}{\mu_0}$

$10^{-17} \mu_0$

$10^{-6} \mu_0$

$10^{-7} \mu_0$

MHT CET 2024 4th May Morning Shift

MCQ (Single Correct Answer)

-0

A charged particle of charge ' $q$ ' is accelerated by a potential difference ' $V$ ' enters a region of uniform magnetic field ' $B$ ' at right angles to the direction of field. The charged particle completes semicircle of radius ' $r$ ' inside magnetic field. The mass of the charged particle is

$\frac{\mathrm{r}^2 q B^2}{2 \mathrm{~V}}$

$\frac{r^2 q^2 B^2}{\sqrt{2} V}$

$\frac{\mathrm{qrB}}{2 \mathrm{~V}}$

$\frac{\mathrm{q}^2 \mathrm{r}^2 \mathrm{~B}^2}{\mathrm{~V}}$

MHT CET 2024 4th May Morning Shift

MCQ (Single Correct Answer)

-0

A charged particle is moving in a uniform magnetic field in a circular path with radius ' $R$ '. When the energy of the particle is doubled, then the new radius will be

$\frac{\mathrm{R}}{\sqrt{2}}$

$ 2 R$

$\frac{\mathrm{R}}{2}$

$\sqrt{2} R$

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