1
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Figure shows two semicircular loops of radii $$R_1$$ and $$R_2$$ carrying current $I$. The magnetic field at the common centre '$$\mathrm{O}$$' is

MHT CET 2023 14th May Evening Shift Physics - Moving Charges and Magnetism Question 14 English

A
$$\frac{\mu_0 \mathrm{I}}{4}\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)$$
B
$$\frac{\mu_0 \mathrm{I}}{4}\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)$$
C
$$\frac{\mu_0 \mathrm{I}}{2 \pi}\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)$$
D
$$\frac{\mu_0 I}{2 \pi}\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$$
2
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A long wire is bent into a circular coil of one turn and then into a circular coil of smaller radius having $$\mathrm{n}$$ turns. If the same current passes in both the cases, the ratio of magnetic fields produced at the centre for one turn to that of $$n$$ turns is

A
$$1: \mathrm{n}$$
B
$$\mathrm{n}: 1$$
C
$$1: \mathrm{n}^2$$
D
$$\mathrm{n}^2: 1$$
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A horizontal wire of mass '$$m$$', length '$$l$$' and resistance '$$R$$' is sliding on the vertical rails on which uniform magnetic field '$$B$$' is directed perpendicular. The terminal speed of the wire as it falls under the force of gravity is ( $$\mathrm{g}=$$ acceleration due to gravity)

A
$$\frac{\mathrm{mg} l}{\mathrm{BR}}$$
B
$$\frac{\mathrm{B}^2 l^2}{\mathrm{mgR}}$$
C
$$\frac{\mathrm{mgR}}{\mathrm{Bl}}$$
D
$$\frac{\mathrm{mgR}}{\mathrm{B}^2 l^2}$$
4
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A straight wire carrying a current (I) is turned into a circular loop. If the magnitude of the magnetic moment associated with it is '$$M$$', then the length of the wire will be

A
$$\frac{\mathrm{M} \pi}{4 \mathrm{I}}$$
B
$$\left[\frac{4 \pi I}{M}\right]^{\frac{1}{2}}$$
C
$$\left[\frac{4 \mathrm{M} \pi}{\mathrm{I}}\right]^{\frac{1}{2}}$$
D
$$4 \pi \mathrm{MI}$$
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