1
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

An element $\overrightarrow{\Delta l}=\Delta \mathrm{xi}$ is placed at the origin and carries a current of 10 A . The magnitude of magnetic field on the Y axis at a distance of 0.5 m if $\Delta x=1 \mathrm{~cm}$ is $\left(\frac{\mu_0}{4 \pi}=10^{-7}\right.$ SI unit $)\left(\sin 90^{\circ}=1\right)$

A
$2 \times 10^{-7} \mathrm{~T}$
B
$10^{-8} \mathrm{~T}$
C
$4 \times 10^{-8} \mathrm{~T}$
D
$2 \times 10^{-8} \mathrm{~T}$
2
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A current ' I ' is flowing in a conductor PQRST as shown in figure. The radius of curved path QRS is ' R ' and length of straight portion PQ and ST is very large. The magnetic field at the centre $[\mathrm{O}]$ of the curved part is ( $\mu_0=$ permeability of free space)

A
$\quad \frac{\mu_0 \mathrm{i}}{4 \pi \mathrm{r}}\left(\frac{3 \pi}{2}+1\right)(-\hat{\mathrm{k}})$
B
$\quad \frac{\mu_0 \mathrm{i}}{4 \pi \mathrm{r}}\left(\frac{3 \pi}{2}+1\right) \hat{\mathrm{k}}$
C
$\frac{\mu_0 \mathrm{i}}{4 \pi \mathrm{r}}\left[\frac{3 \pi}{2}-1\right](-\hat{\mathrm{k}})$
D
$\quad \frac{\mu_0 \mathrm{i}}{4 \pi \mathrm{r}}\left[\frac{3 \pi}{2}-1\right] \hat{\mathrm{k}}$
3
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A wire has three different sections as shown in figure. The magnitude of the magnetic field produced at the centre ' $O$ ' of the semicircle by three sections together is ( $\mu_0=$ permiability of free space)

MHT CET 2025 20th April Morning Shift Physics - Moving Charges and Magnetism Question 1 English
A
$\frac{\mu_0 \mathrm{I}}{4 \mathrm{R}}$
B
$\frac{\mu_0 \mathrm{I}}{2 \mathrm{R}}$
C
$\frac{\mu_0 \mathrm{I}}{4 \pi \mathrm{R}}$
D
$\frac{\mu_0 I}{2 \pi R}$
4
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A long wire carrying a steady current is bent into a circle of single turn. The magnetic field at the centre of the coil is ' B '. If it is bent into a circular loop of radius ' $\mathrm{r}_1$ ' having ' n ' turns, the magnetic field at the centre of the coil for same current is

A
$\frac{B}{n^2}$
B
$\frac{B}{n}$
C
$n^2 B$
D
nB
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