1
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic induction due to an ideal solenoid is independent of

A
total number of turns of the wire.
B
length of the solenoid.
C
radius of the wire.
D
current carried by the wire.
2
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic field intensity inside current carrying solenoid is $\mathrm{H}=2.4 \times 10^3 \mathrm{~A} / \mathrm{m}$. If length and number of turns of a solenoid is 15 cm and 60 turns respectively. The current flowing in the solenoid is

A
4 A
B
6 A
C
0.6 A
D
60 A
3
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle carrying a charge equal to 100 times the charge on an electron is rotating one rotation per second in a circular path of radius 0.8 m . The value of magnetic field produced at the centre will be ( $\mu_0=$ permeability of vacuum)

A
$\frac{10^{-7}}{\mu_0}$
B
$10^{-17} \mu_0$
C
$10^{-6} \mu_0$
D
  $10^{-7} \mu_0$
4
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A charged particle of charge ' $q$ ' is accelerated by a potential difference ' $V$ ' enters a region of uniform magnetic field ' $B$ ' at right angles to the direction of field. The charged particle completes semicircle of radius ' $r$ ' inside magnetic field. The mass of the charged particle is

A
$\frac{\mathrm{r}^2 q B^2}{2 \mathrm{~V}}$
B
$\frac{r^2 q^2 B^2}{\sqrt{2} V}$
C
$\frac{\mathrm{qrB}}{2 \mathrm{~V}}$
D
$\frac{\mathrm{q}^2 \mathrm{r}^2 \mathrm{~B}^2}{\mathrm{~V}}$
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