1
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A long straight wire carrying a current of $$25 \mathrm{~A}$$ rests on the table. Another wire PQ of length $$1 \mathrm{~m}$$ and mass $$2.5 \mathrm{~g}$$ carries the same current but in the opposite direction. The wire PQ is free to slide up and down. To what height will wire PQ rise? ($$\mu_0=4 \pi \times 10^{-7}$$ SI unit)

MHT CET 2023 9th May Morning Shift Physics - Moving Charges and Magnetism Question 9 English

A
3 mm
B
4 mm
C
5 mm
D
8 mm
2
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

A, B and C are three parallel conductors of equal lengths carrying currents $$\mathrm{I}, \mathrm{I}$$ and $$2 \mathrm{I}$$ respectively. Distance between A and B is '$$x$$' and that between B and C is also '$$x$$'. $$F_1$$ is the force exerted by conductor $$\mathrm{B}$$ on $$\mathrm{A}$$. $$\mathrm{F}_2$$ is the force exerted by conductor $$\mathrm{C}$$ on $$\mathrm{A}$$. Current $$\mathrm{I}$$ in $$\mathrm{A}$$ and $$\mathrm{I}$$ in $$\mathrm{B}$$ are in same direction and current $$2 \mathrm{I}$$ in $$\mathrm{C}$$ is in opposite direction. Then

A
$$\mathrm{F}_1=\mathrm{F}_2$$
B
$$\mathrm{F}_2=2 \mathrm{R}_1$$
C
$$F_1=2 R_2$$
D
$$F_1=-F_2$$
3
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Magnetic moment of revolving electron of charge (e) and mass (m) in terms of angular momentum (L) of electron is :

A
$$\frac{e L}{8 m}$$
B
$$\frac{\mathrm{eL}}{4 \mathrm{~m}}$$
C
$$\frac{\mathrm{eL}}{2 \mathrm{~m}}$$
D
$$\frac{\mathrm{eL}}{\mathrm{m}}$$
4
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic flux near the axis and inside the air core solenoid of length $$60 \mathrm{~cm}$$ carrying current '$$\mathrm{I}$$' is $$1.57 \times 10^{-6} \mathrm{~Wb}$$. Its magnetic moment will be $$\left[\mu_0=4 \pi \times 10^{-7}\right.$$, SI unit and crosssectional area is very small as compared to length of solenoid.]

A
$$1 ~\mathrm{Am}^2$$
B
$$0.25 ~\mathrm{Am}^2$$
C
$$0.5 ~\mathrm{Am}^2$$
D
$$0.75 ~\mathrm{Am}^2$$
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