1
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The contrapositive of "If $$x$$ and $$y$$ are integers such that $$x y$$ is odd, then both $$x$$ and $$y$$ are odd" is

A
If both $$x$$ and $$y$$ are odd integers, then $$x y$$ is odd.
B
If both $$x$$ and $$y$$ are even integers, then $$x y$$ is even.
C
If $$x$$ or $$y$$ is an odd integer, then $$x y$$ is odd.
D
If both $$x$$ and $$y$$ are not odd integers, then the product $$x y$$ is not odd.
2
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The logical statement $$(\sim(\sim \mathrm{p} \vee \mathrm{q}) \vee(\mathrm{p} \wedge \mathrm{r})) \wedge(\sim \mathrm{q} \wedge \mathrm{r})$$ is equivalent to

A
$$\sim p \vee r$$
B
$$(p \wedge \sim q) \vee r$$
C
$$(\mathrm{p} \wedge \mathrm{r}) \wedge \sim \mathrm{q}$$
D
$$(\sim p \wedge \sim q) \wedge r$$
3
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If truth value of logical statement $$(p \leftrightarrow \sim q) \rightarrow(\sim p \wedge q)$$ is false, then the truth values of $$p$$ and $$q$$ are respectively

A
$$\mathrm{F}, \mathrm{T}$$
B
$$\mathrm{T}, \mathrm{T}$$
C
$$\mathrm{T}, \mathrm{F}$$
D
$$\mathrm{F,F}$$
4
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The statement pattern $$\mathrm{p} \rightarrow \sim(\mathrm{p} \wedge \sim \mathrm{q})$$ is equivalent to

A
$$\mathrm{q}$$
B
$$(\sim p) \vee q$$
C
$$(\sim p) \wedge q$$
D
$$(\sim p) \vee(\sim q)$$
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