$$\int_\limits0^{\pi / 4} \log (1+\tan x) d x=$$

If $$\int_\limits0^{\frac{\pi}{2}} \frac{d x}{5+4 \sin x}=A \tan ^{-1} B$$, then A + B =

$$\int_0^a \sqrt{\frac{x}{a-x}} d x=$$

$$\int_\limits2^3 \frac{x}{x^2-1} d x=$$