1
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

In $$\triangle A B C$$ with usual notation, $$\frac{\cos A}{a}=\frac{\cos B}{b}=\frac{\cos C}{c}$$ and $$a=\frac{1}{\sqrt{6}}$$, then the area of triangle is _______ sq. units.

A
$$\frac{1}{8}$$
B
$$\frac{1}{24 \sqrt{3}}$$
C
$$\frac{1}{24}$$
D
$$\frac{1}{8 \sqrt{3}}$$
2
MHT CET 2023 13th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Angles of a triangle are in the ratio $$4: 1: 1$$. Then the ratio of its greatest side to its perimeter is

A
$$3:(2+\sqrt{3})$$
B
$$\sqrt{3}:(2+\sqrt{3})$$
C
$$\sqrt{3}:(2-\sqrt{3})$$
D
$$1:(2+\sqrt{3})$$
3
MHT CET 2023 12th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The lengths of sides of a triangle are three consecutive natural numbers and its largest angle is twice the smallest one. Then the length of the sides of the triangle (in units) are

A
$$3,4,5$$
B
$$4,5,6$$
C
$$5,6,7$$
D
$$2,3,4$$
4
MHT CET 2023 12th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If two angles of $$\triangle \mathrm{ABC}$$ are $$\frac{\pi}{4}$$ and $$\frac{\pi}{3}$$, then the ratio of the smallest and greatest sides are

A
$$(\sqrt{3}-1): 1$$
B
$$\sqrt{3}: \sqrt{5}$$
C
$$\sqrt{2}: \sqrt{3}$$
D
$$(\sqrt{3}-1): 4$$
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