MHT CET 2024 9th May Evening Shift | Current Electricity Question 20 | Physics

In an ammeter, $4 \%$ of the main current is passing through the galvanometer, If shunt resistance is $5 \Omega$, then resistance of galvanometer will be

$60 \Omega$

$120 \Omega$

$240 \Omega$

$480 \Omega$

MHT CET 2024 9th May Morning Shift

MCQ (Single Correct Answer)

-0

When the two known resistance ' $R$ ' and ' $S$ ' are connected in the left and right gaps of a meter bridge respectively, the null point is found at a distance ' $l_1$ ' from the zero end of a meter bridge wire. An unknown resistance ' X ' is now connected in parallel with ' S ' and null point is found at a distance ' $l_2$ ' form zero end of meter bridge wire. The unknown resistance ' X ' is

$\frac{\mathrm{S} l_1\left(100-l_2\right)}{100\left(l_2-l_1\right)}$

$\frac{\mathrm{S} l_2\left(100-l_1\right)}{100\left(l_1-l_2\right)}$

$\frac{100\left(l_2-l_1\right)}{\mathrm{Sl}_1\left(100-l_2\right)}$

$\frac{100\left(l_2-l_1\right)}{\mathrm{S} l_2\left(100-l_1\right)}$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

In a Wheatstone's bridge, the resistances in four arms are as shown in the figure. The balancing condition of the bridge is

MHT CET 2024 4th May Evening Shift Physics - Current Electricity Question 21 English

$\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{R}}{\mathrm{S}_1+\mathrm{S}_2}$

$\frac{P}{Q}=\frac{R\left(S_1 S_2\right)}{S_1+S_2}$

$\frac{P}{Q}=\frac{R\left(S_1+S_2\right)}{2 S_1 S_2}$

$\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{R}\left(\mathrm{S}_1+\mathrm{S}_2\right)}{\mathrm{S}_1 \mathrm{~S}_2}$

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