MHT CET 2020 16th October Morning Shift | Current Electricity Question 56 | Physics

A potentiometer wire is $$4 \mathrm{~m}$$ long and potential difference of $$3 \mathrm{~V}$$ is maintained between the ends. The emf of the cell, which balances against a length of $$100 \mathrm{~cm}$$ of the potentiometer wire is

0.60 V

0.50 V

0.25 V

0.75 V

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

A potentiometer wire has length $L$ For given cell of emf $E$, the balancing length is $\frac{L}{3}$ from the positive end of the wire. If the length of potentiometer wire is increased by $50 \%$, then for the same cell, the balance point is obtained at length

$\frac{L}{2}$ from positive end

$\frac{L}{5}$ from positive end

$\frac{L}{3}$ from positive end

$\frac{L}{4}$ from positive end

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

In the network shown cell E has internal resistance $r$ and the galvanometer shows zero deflection. If the cell is replaced by a new cell of emf $2 E$ and internal resistance $3 r$ keeping everything else identical, then

MHT CET 2019 3rd May Morning Shift Physics - Current Electricity Question 2 English

The galvanometer will show deflection of 10 divisions.

The galvanometer show zero deflection,

Current will flow from $B$ to $A$.

Current will flow from $A$ to $B$.

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

The range of an ammeter of resistance ' $G$ can be increased from ' $I$ ' to ' $nI$ ' by connecting

a series resistance of $\frac{G}{n+1} \Omega$

a shunt of $\frac{G}{n-1} \Omega$

a shunt of $\frac{G}{n+1} \Omega$

a series resistance of $\frac{G}{n-1} \Omega$

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