1
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+1
-0

A potentiometer wire is $$4 \mathrm{~m}$$ long and potential difference of $$3 \mathrm{~V}$$ is maintained between the ends. The emf of the cell, which balances against a length of $$100 \mathrm{~cm}$$ of the potentiometer wire is

A
0.60 V
B
0.50 V
C
0.25 V
D
0.75 V
2
MHT CET 2019 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A potentiometer wire has length $L$ For given cell of emf $E$, the balancing length is $\frac{L}{3}$ from the positive end of the wire. If the length of potentiometer wire is increased by $50 \%$, then for the same cell, the balance point is obtained at length

A
$\frac{L}{2}$ from positive end
B
$\frac{L}{5}$ from positive end
C
$\frac{L}{3}$ from positive end
D
$\frac{L}{4}$ from positive end
3
MHT CET 2019 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In the network shown cell E has internal resistance $r$ and the galvanometer shows zero deflection. If the cell is replaced by a new cell of emf $2 E$ and internal resistance $3 r$ keeping everything else identical, then

MHT CET 2019 3rd May Morning Shift Physics - Current Electricity Question 46 English

A
The galvanometer will show deflection of 10 divisions.
B
The galvanometer show zero deflection,
C
Current will flow from $B$ to $A$.
D
Current will flow from $A$ to $B$.
4
MHT CET 2019 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The range of an ammeter of resistance ' $G$ can be increased from ' $I$ ' to ' $nI$ ' by connecting

A
a series resistance of $\frac{G}{n+1} \Omega$
B
a shunt of $\frac{G}{n-1} \Omega$
C
a shunt of $\frac{G}{n+1} \Omega$
D
a series resistance of $\frac{G}{n-1} \Omega$
MHT CET Subjects
EXAM MAP