1
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

A particle is moving on a straight line. The distance $$\mathrm{S}$$ travelled in time $$\mathrm{t}$$ is given by $$\mathrm{S=a t^2+b t+6}$$. If the particle comes to rest after 4 seconds at a distance of $$16 \mathrm{~m}$$. from the starting point, then the acceleration of the particle is.

A
$$\frac{-3}{4} \mathrm{~m} / \mathrm{sec}^2$$
B
$$\frac{-1}{2} \mathrm{~m} / \mathrm{sec}^2$$
C
$$-1 \mathrm{~m} / \mathrm{sec}^2$$
D
$$\frac{-5}{4} \mathrm{~m} / \mathrm{sec}^2$$
2
MHT CET 2021 20th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

The equation of the tangent to the curve $$y = 4x{e^x}$$ at $$\left( { - 1,{{ - 4} \over e}} \right)$$ is

A
$$6x - {e \over 4}y = - 5$$
B
$$x - {e \over 4}y = 0$$
C
$$x = - 1$$
D
$$y = {{ - 4} \over e}$$
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