MHT CET 2023 14th May Morning Shift | Electrostatics Question 49 | Physics

A conducting sphere of radius $$0.1 \mathrm{~m}$$ has uniform charge density $$1.8 \mu \mathrm{C} / \mathrm{m}^2$$ on its surface. The electric field in free space at radial distance $$0.2 \mathrm{~m}$$ from a point on the surface is ( $$\varepsilon_0=$$ permittivity of free space)

$$\frac{6 \times 10^{-6}}{\varepsilon_0} \mathrm{Vm}^{-1}$$

$$\frac{6 \times 10^{-8}}{\varepsilon_0} \mathrm{Vm}^{-1}$$

$$\frac{2 \times 10^{-7}}{\varepsilon_0} \mathrm{Vm}^{-1}$$

$$\frac{1 \times 10^{-7}}{\varepsilon_0} \mathrm{Vm}^{-1}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

The work done in rotating a dipole placed parallel to the electric field through $$180^{\circ}$$ is W. So, the work done in rotating it through $$60^{\circ}$$ is $$\left(\cos 0^{\circ}=1, \cos 60^{\circ}=\frac{1}{2}, \cos 180^{\circ}=-1\right)$$

$$4 W$$

$$3 \mathrm{~W}$$

$$W / 2$$

$$W / 4$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

In the electric field due to a charge $$Q$$, a charge $$q$$ moves from point $$A$$ to $$B$$. The work done is ( $$\varepsilon_0=$$ permittivity of vacuum)

MHT CET 2023 13th May Evening Shift Physics - Electrostatics Question 68 English

$$\frac{1}{4 \pi \varepsilon_0} \frac{Q q}{r^2}$$

$$\frac{1}{4 \pi \varepsilon_0} \frac{Q q}{r} \times \frac{\pi}{6}$$

$$\frac{1}{4 \pi \varepsilon_0} \frac{Q q}{r}$$

Zero

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

-0

Which of the following statements is 'WRONG' for the conductors?

In static situation, the interior of conductor can have no charge.

The net electrostatic field is zero in the interior of a conductor.

The electrostatic field just outside the surface of charged conductor must be tangential to the surface at any point.

The electrostatic potential is constant within and on the surface of a conductor.

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