MHT CET 2026 18th April Morning Shift | Moving Charges and Magnetism Question 14 | Physics

In the following figure, the magnitude of the magnetic field at point 'O' will be
MHT CET 2026 18th April Morning Shift Physics - Moving Charges and Magnetism Question 8 English

MHT CET 2026 18th April Morning Shift Physics - Moving Charges and Magnetism Question 8 English

$\dfrac{\mu_0}{4\pi}\dfrac{I}{r}\left(\dfrac{2}{\pi}+2\right)$

$\dfrac{\mu_0}{4\pi}\dfrac{I}{r}\left(\dfrac{2}{\pi}-2\right)$

$\dfrac{\mu_0}{4\pi}\dfrac{I}{r}\left(2+\dfrac{\pi}{2}\right)$

$\dfrac{\mu_0}{4\pi}\dfrac{I}{r}\left(2-\dfrac{\pi}{2}\right)$

MHT CET 2026 18th April Morning Shift

MCQ (Single Correct Answer)

-0

The ratio of magnetic field at the centre of the current carrying circular loop and its magnetic moment is '$x$'. When both the current and radius are tripled, then the ratio will be

$\dfrac{x}{27}$

$\dfrac{x}{9}$

$\dfrac{x}{3}$

$3x$

MHT CET 2026 17th April Evening Shift

MCQ (Single Correct Answer)

-0

The current passing through the galvanometer is 4 % of the total current in the curcuit. If the resistance of the galvanometer is 'G', the shunt resistance 'S' connected across the galvanometer is

$25\,G$

$24\,G$

$\dfrac{G}{24}$

$\dfrac{G}{25}$

MHT CET 2026 17th April Evening Shift

MCQ (Single Correct Answer)

-0

Two wires of same length are bent to form the circular loop with two turns and a square loop of one turn. Both of them carry same current. The ratio of magnetic moment of circular loop of two turns to that of square loop is

$\pi : 4$

$4 : \pi$

$\pi : 1$

$2 : \pi$

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