MHT CET 2026 17th April Evening Shift | Moving Charges and Magnetism Question 19 | Physics

The magnetic field at the center of circular coil carrying current '$I$' for a single turn of a given length of wire is '$B$'. The same wire is bent in a circular coil having two turns. When the same current passes through it, the value of magnetic field becomes

$4B$

$2B$

$\dfrac{B}{2}$

$\dfrac{B}{4}$

MHT CET 2026 17th April Morning Shift

MCQ (Single Correct Answer)

-0

The magnetic field at perpendicular distance '$r$' from a long wire carrying current '$I$' is '$B$'. The magnetic field at perpendicular distance '$2r$' from the same wire is

$\dfrac{B}{4}$

$\dfrac{B}{2}$

$2B$

$4B$

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

A wire of length ' $L$ ' carries a current ' $I$ '. If the wire is turned into a square coil of single turn, the maximum magnitude of the torque in a given magnetic field $(\overrightarrow{\mathrm{B}})$ is

$\frac{\mathrm{IBL}}{16}$

$\frac{\mathrm{IBL}}{8}$

$\frac{\mathrm{IBL}^2}{8}$

$\frac{\mathrm{IBL}^2}{16}$

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