1
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $y = \tan^{-1}\left(\dfrac{\log\left(\dfrac{e}{x^3}\right)}{\log ex^3}\right) + \tan^{-1}\left(\dfrac{\log(e^4x^3)}{\log\left(\dfrac{e}{x^{12}}\right)}\right)$, $x \in \left(e^{-\frac{1}{3}}, e^{\frac{1}{12}}\right)$ then $\dfrac{dy}{dx}$ is equal to...
A
$1$
B
$0$
C
$-1$
D
$\dfrac{1}{e}$
2
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $0 \leq x \leq 1$ and $(\sin^{-1}x)^3 + (\cos^{-1}x)^3 = a\pi^3$ then
A
$a \geq \dfrac{1}{32}$
B
$a \geq \dfrac{1}{16}$
C
$a \leq \dfrac{1}{32}$
D
$a \leq \dfrac{1}{16}$
3
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $\sum\limits_{n=1}^{2026}\tan^{-1}\left(\dfrac{1}{n^2+n+1}\right) = \tan^{-1}\left(1 - \dfrac{1}{x}\right)$, where $x \neq 0$, then $x = $
A
$2028$
B
$2026$
C
$1014$
D
$1013$
4
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\sin^{-1}(x - 2) + \cos^{-1}(x) + \tan^{-1}(x + 2) + \cot^{-1}(x + 4) = \sec^{-1}(\sqrt{k}) - \dfrac{\pi}{2}$, then $\cos(2\,\text{cosec}^{-1}\sqrt{k - 1}) = \ldots$
A
$\dfrac{15}{16}$
B
$\dfrac{31}{32}$
C
$\dfrac{63}{64}$
D
$\dfrac{7}{8}$

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