1
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
For $x > 0$, if $\sin(\cos^{-1}x + \tan^{-1}x) - \cos(\sin^{-1}x + \tan^{-1}x) = \sin(\cot^{-1}2)$ then $x = $
A
$\dfrac{1}{\sqrt{2}}$
B
$\dfrac{1}{2}$
C
$\dfrac{\sqrt{3}}{2}$
D
$1$
2
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\tan^{-1}ax + \tan^{-1}3x = \dfrac{\pi}{4}$, where $3ax^2 < 1$, then value of $a$ for $x = \dfrac{1}{6}$ is $\ldots$
A
$2$
B
$3$
C
$4$
D
$9$
3
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\sec^2(\tan^{-1}3) - \tan^2(\sec^{-1}3) = $
A
$0$
B
$1$
C
$2$
D
$3$
4
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $y = \tan^{-1}\left(\dfrac{\log\left(\dfrac{e}{x^3}\right)}{\log ex^3}\right) + \tan^{-1}\left(\dfrac{\log(e^4x^3)}{\log\left(\dfrac{e}{x^{12}}\right)}\right)$, $x \in \left(e^{-\frac{1}{3}}, e^{\frac{1}{12}}\right)$ then $\dfrac{dy}{dx}$ is equal to...
A
$1$
B
$0$
C
$-1$
D
$\dfrac{1}{e}$

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