1
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$\left[\sin \left(\tan ^{-1} \frac{3}{4}\right)\right]^2+\left[\sin \left(\tan ^{-1} \frac{4}{3}\right)\right]^2=$$

A
0
B
1
C
5
D
$$-$$1
2
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+2
-0

The value of $$\tan ^{-1}\left(\frac{1}{3}\right)+\tan ^{-1}\left(\frac{1}{5}\right)+\tan ^{-1}\left(\frac{1}{7}\right)+\tan ^{-1}\left(\frac{1}{8}\right)$$ is

A
$$\frac{\pi}{6}$$
B
$$\frac{\pi}{3}$$
C
$$\frac{\pi}{4}$$
D
$$\frac{\pi}{12}$$
3
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

The value of $$\sin ^{-1}\left(-\frac{1}{2}\right)+\cos ^{-1}\left(-\frac{\sqrt{3}}{2}\right)$$ is

A
$$\cos ^{-1}\left(\frac{1}{2}\right)$$
B
$$\cos ^{-1}\left(-\frac{\sqrt{3}}{2}\right)$$
C
$$\cos ^{-1}\left(-\frac{1}{2}\right)$$
D
$$\sin ^{-1}\left(-\frac{1}{2}\right)$$
4
MHT CET 2019 3rd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $y=\tan ^{-1}\left(\frac{1-\cos 3 x}{\sin 3 x}\right)$, then $\frac{d y}{d x}=$ .......

A
$-\frac{3}{2}$
B
$-\frac{1}{2}$
C
$\frac{3}{2}$
D
$\frac{1}{2}$
MHT CET Subjects
EXAM MAP