1
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\cos^{-1}\left(\cos\dfrac{4\pi}{3}\right) + \sin^{-1}\left(\sin\dfrac{4\pi}{3}\right) = \ldots$
A
$\dfrac{4\pi}{3}$
B
$\dfrac{8\pi}{3}$
C
$\dfrac{\pi}{3}$
D
$\dfrac{3\pi}{2}$
2
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The value of $3\tan^{-1}\left(\dfrac{1}{2}\right) = \ldots$
A
$\tan^{-1}\left(\dfrac{5}{2}\right)$
B
$\tan^{-1}\left(\dfrac{2}{5}\right)$
C
$\cot^{-1}\left(\dfrac{11}{2}\right)$
D
$\tan^{-1}\left(\dfrac{11}{2}\right)$
3
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The value of $\cot^{-1}\left[\dfrac{\sqrt{1 - \sin x} + \sqrt{1 + \sin x}}{\sqrt{1 - \sin x} - \sqrt{1 + \sin x}}\right]$, where $x \in \left(0, \dfrac{\pi}{2}\right)$ is...
A
$\pi - x$
B
$2\pi - x$
C
$\dfrac{\pi}{2} - \dfrac{x}{2}$
D
$\pi - \dfrac{x}{2}$
4
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $(\tan^{-1}x)^2 + (\cot^{-1}x)^2 = \dfrac{5\pi^2}{8}$, then the value of $x$ is equal to...
A
$-1$
B
$-2$
C
$1$
D
$2$

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