1
GATE EE 2006
MCQ (Single Correct Answer)
+2
-0.6
Consider the following Nyquist plots of loop transfer functions over $$\omega = 0$$ to $$\omega = \infty .$$ Which of these plots represents a stable closed loop system? GATE EE 2006 Control Systems - Polar Nyquist and Bode Plot Question 12 English 1 GATE EE 2006 Control Systems - Polar Nyquist and Bode Plot Question 12 English 2 GATE EE 2006 Control Systems - Polar Nyquist and Bode Plot Question 12 English 3 GATE EE 2006 Control Systems - Polar Nyquist and Bode Plot Question 12 English 4
A
$$(1)$$ only
B
all, except $$(1)$$
C
all, except $$(3)$$
D
$$(1)$$ and $$(2)$$ only
2
GATE EE 2005
MCQ (Single Correct Answer)
+2
-0.6
In the $$GH(s)$$ plane, the Nyquist plot of the loop transfer function $$G\left( s \right)\,H\left( s \right) = {{\pi {e^{ - 0.25s}}} \over s}$$ passes through the negative real axis at the point
A
$$\left( { - 0.25,j0} \right)$$
B
$$\left( { - 0.5,j0} \right)$$
C
$$\left( { - 1,j0} \right)$$
D
$$\left( { - 2,j0} \right)$$
3
GATE EE 2005
MCQ (Single Correct Answer)
+2
-0.6
If the compensated system shown in the figure has a phase margin of $${60^ \circ }$$ at the crossover frequency of $$1 rad/sec,$$ the value of the gain $$K$$ is GATE EE 2005 Control Systems - Polar Nyquist and Bode Plot Question 29 English
A
$$0.366$$
B
$$0.732$$
C
$$1.366$$
D
$$2.738$$
4
GATE EE 2004
MCQ (Single Correct Answer)
+2
-0.6
In the system shown in figure, the input $$x(t)$$ $$=$$ $$sin$$ $$t.$$ In the steady-state, the response $$y(t)$$ will be GATE EE 2004 Control Systems - Polar Nyquist and Bode Plot Question 32 English
A
$${K \over {\sqrt 2 }}\sin \left( {t - {{45}^0}} \right)$$
B
$${K \over {\sqrt 2 }}\sin \left( {t + {{45}^0}} \right)$$
C
$$K\,\sin \left( {t - {{45}^0}} \right)$$
D
$$K\,\sin \left( {t + {{45}^0}} \right)$$
GATE EE Subjects
EXAM MAP