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1
JEE Advanced 2026 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1

For a reversible reaction $R \rightleftharpoons P$, at constant temperature, both the forward and the backward reactions are first order elementary reactions with rate constants $k_{{f}}$ and $k_{{b}}$, respectively. At time zero, the concentration of $R$ is $[R]_0$ and the concentration of $P$ is zero. At any given time, $[R]$ and $[P]$ are the concentrations of $R$ and $P$, respectively. If $k_{{b}} = 4k_{{f}}$, the correct graphical representation of the reaction is

A
JEE Advanced 2026 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 2 English Option 1
B
JEE Advanced 2026 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 2 English Option 2
C
JEE Advanced 2026 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 2 English Option 3
D
JEE Advanced 2026 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 2 English Option 4
2
JEE Advanced 2026 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1

The correct order of dipole moments for the given species is

A

BF$_3$ = NH$_4^+$ < NF$_3$ < NH$_3$

B

BF$_3$ < NH$_4^+$ < NF$_3$ < NH$_3$

C

NH$_4^+$ < BF$_3$ < NH$_3$ < NF$_3$

D

BF$_3$ < NH$_4^+$ < NH$_3$ < NF$_3$

3
JEE Advanced 2026 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1

Considering LiBH4 reduces an ester group to the corresponding alcohol and does not reduce a carboxylic acid group, the correct statement about the major products P, Q, R and S is:

JEE Advanced 2026 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 6 English
A

P & Q are identical, and R & S are diastereomers.

B

P & Q are diastereomers, and R & S are identical.

C

P & Q are diastereomers, and R & S are diastereomers.

D

P & Q are identical, and R & S are identical.

4
JEE Advanced 2026 Paper 1 Online
MCQ (More than One Correct Answer)
+4
-1

The 2s and the 2p orbital energies of hydrogen atom are $E_{2s}({H})$ and $E_{2p}({H})$, respectively. The 2s and the 2p orbital energies of lithium atom are $E_{2s}({Li})$ and $E_{2p}({Li})$, respectively. The correct option(s) about the orbital energies is(are)

A

$E_{2s}({Li}) < E_{2p}({Li})$

B

$E_{2s}({H}) = E_{2p}({H})$

C

$E_{2p}({H}) < E_{2s}({Li})$

D

$E_{2s}({H}) > E_{2s}({Li})$

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