1
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
Two indentical metal plates are given charges $q_1$ and $q_2$ $(q_2 < q_1)$ respectively. They are brought close together to form a parallel plate capacitor with capacitance 'C'. The potential difference 'V' between the plates is
A
$\dfrac{q_1 - q_2}{C}$
B
$\dfrac{q_1 + q_2}{C}$
C
$\dfrac{q_1 - q_2}{2C}$
D
$\dfrac{q_1 + q_2}{2C}$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
If the equivalent capacitance between points A and B of the combination of capacitors shown in figure, is 6C, the capacitor $C^1$ is
MHT CET 2026 17th April Evening Shift Physics - Capacitor Question 11 English
A
$9C$
B
$15C$
C
$18C$
D
$24C$
3
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Three capacitors $C_1$, $C_2$ and $C_3$ are connected to voltage source V as shown in figure. The voltage across $C_3$ will be
MHT CET 2026 17th April Morning Shift Physics - Capacitor Question 10 English
A
$\dfrac{C_3 V}{(C_1+C_2+C_3)}$
B
$\dfrac{(C_1+C_2)V}{C_3}$
C
$\dfrac{(C_2+C_3)V}{C_1+C_2}$
D
$\dfrac{(C_1+C_2)V}{(C_1+C_2+C_3)}$
4
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two capacitors, $C_1$ and $C_2$ have their capacitances in the ratio 1:2. $V_s$ and $V_p$ are the potential differences applied across the series and parallel combination of $C_1$ and $C_2$ respectively, so that the energy stored in the two cases becomes same. The ratio $V_s$ to $V_p$ is
A
$\sqrt{2} : 3$
B
$3 : \sqrt{2}$
C
$2 : \sqrt{3}$
D
$\sqrt{3} : 2$

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