1
MHT CET 2023 9th May Morning Shift
+1
-0

The capacitance of a parallel plate capacitor is $$2.5 ~\mu \mathrm{F}$$. When it is half filled with a dielectric as shown in figure, its capacitance becomes $$5 ~\mu \mathrm{F}$$. The dielectric constant of the dielectric is

A
7.5
B
3
C
4
D
5
2
MHT CET 2023 9th May Morning Shift
+1
-0

The ratio of potential difference that must be applied across parallel and series combination of two capacitors $$C_1$$ and $$C_2$$ with their capacitance in the ratio $$1: 2$$ so that energy stored in these two cases becomes same is

A
$$3: \sqrt{2}$$
B
$$\sqrt{2}: 3$$
C
$$2: 9$$
D
$$9: 2$$
3
MHT CET 2023 9th May Morning Shift
+1
-0

The potential energy of charged parallel plate capacitor is $$v_0$$. If a slab of dielectric constant $$\mathrm{K}$$ is inserted between the plates, then the new potential energy will be

A
$$\frac{v_0}{\mathrm{~K}}$$
B
$$v_0 \mathrm{~K}^2$$
C
$$\frac{v_0}{\mathrm{~K}^2}$$
D
$$\mathrm{v}_0^2$$
4
MHT CET 2022 11th August Evening Shift
+1
-0

A parallel plate air capacitor has a uniform electric field 'E' in the space between the plates. Area of each plate is A and the distance between the plates is '$$\mathrm{d}$$'. The energy stored in the capacitor is $$\left[\varepsilon_0=\right.$$ permittivity of free space)

A
$$2 \varepsilon_0 \mathrm{EAd}$$
B
$$\frac{1}{2} \varepsilon_0 \mathrm{E}^2 \mathrm{Ad}$$
C
$$\frac{\varepsilon_0 \mathrm{E}^2}{2 \mathrm{Ad}}$$
D
$$\frac{\mathrm{E}^2 \mathrm{Ad}}{2 \varepsilon_0}$$
EXAM MAP
Medical
NEET