1
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two identical capacitors have the same capacitance '$$C$$'. One of them is charged to a potential $$V_1$$ and the other to $$V_2$$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is

A
$$\frac{1}{4} \mathrm{C}\left(\mathrm{V}_1^2-\mathrm{V}_2^2\right)$$
B
$$\frac{1}{4} \mathrm{C}\left(\mathrm{V}_1^2+\mathrm{V}_2^2\right)$$
C
$$\frac{1}{4} \mathrm{C}\left(\mathrm{V}_1-\mathrm{V}_2\right)^2$$
D
$$\frac{1}{4} \mathrm{C}\left(\mathrm{V}_1+\mathrm{V}_2\right)^2$$
2
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If a capacitor of capacity $$900 ~\mu \mathrm{F}$$ is charged to $$100 \mathrm{~V}$$ and its total energy is transferred to a capacitor of capacity $$100 ~\mu \mathrm{F}$$, then its potential will be

A
$$30 \mathrm{~V}$$
B
$$200 \mathrm{~V}$$
C
$$300 \mathrm{~V}$$
D
$$400 \mathrm{~V}$$
3
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two dielectric slabs having dielectric constant '$$\mathrm{K}_1$$' and '$$\mathrm{K}_2$$' of thickness $$\frac{\mathrm{d}}{4}$$ and $$\frac{3 \mathrm{~d}}{4}$$ are inserted between the plates as shown in figure. The net capacitance between $$A$$ and $$B$$ is $$\left[\varepsilon_0\right.$$ is permittivity of free space]

MHT CET 2023 10th May Evening Shift Physics - Capacitor Question 16 English

A
$$\frac{2 \mathrm{~A} \varepsilon_0}{\mathrm{~d}}\left[\frac{\mathrm{K}_1 \mathrm{~K}_2}{3 \mathrm{~K}_1+\mathrm{K}_2}\right]$$
B
$$\frac{3 \mathrm{~A} \varepsilon_0}{\mathrm{~d}}\left[\frac{\mathrm{K}_1+\mathrm{K}_2}{\mathrm{~K}_1 \mathrm{~K}_2}\right]$$
C
$$\frac{3 \mathrm{~A}_0}{2 \mathrm{~d}}\left[\frac{\mathrm{K}_1+\mathrm{K}_2}{\mathrm{~K}_1 \mathrm{~K}_2}\right]$$
D
$$\frac{4 A \varepsilon_0}{d}\left[\frac{K_1 K_2}{3 K_1+K_2}\right]$$
4
MHT CET 2023 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A parallel plate capacitor has plate area '$$\mathrm{A}$$' and separation between plates is '$$d$$'. It is charged to a potential difference of $$\mathrm{V}_0$$ volt. The charging battery is then disconnected and plates are pulled apart three times the initial distance. The work done to increase the distance between the plates is $$\left(\varepsilon_0=\right.$$ permittivity of free space)

A
$$\frac{3 \varepsilon_0 \mathrm{AV}_0{ }^2}{\mathrm{~d}}$$
B
$$\frac{\varepsilon_0 \mathrm{AV}_0^2}{2 \mathrm{~d}}$$
C
$$\frac{\varepsilon_0 \mathrm{AV}_0{ }^2}{3 \mathrm{~d}}$$
D
$$\frac{\varepsilon_0 \mathrm{AV}_0{ }^2}{\mathrm{~d}}$$
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