1
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two parallel plate air c apacitors of same capacity ' C ' are connected in parallel to a battery of e.m.f. ' $E$ '. Then one of the capacitors is completely filled with dielectric mnaterial of constant ' K '. The change in the effective capacity of the parallel combination is

A
$\frac{\mathrm{C}}{(\mathrm{K}-1)}$
B
$\frac{\mathrm{KC}}{\mathrm{K}-1}$
C
$\mathrm{KC}+1$
D
$\mathrm{C}(\mathrm{K}-1)$
2
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
The plates of a parallel plate capacitor are separated by a distance 'd' with air as the medium between them. A dielectric slab of dielectric constant 3 is introduced between the plates so as to increase the capacity by $50 \%$. The thickness of the dielectric slab is
A
$\frac{\mathrm{d}}{2}$
B
$\frac{\mathrm{d}}{3}$
C
$\frac{\mathrm{d}}{5}$
D
$\frac{5 \mathrm{~d}}{6}$
3
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The graph shows the variation of voltage ' V ' across the plates of two capacitors $A$ and $B$ versus increase in charge ' $Q$ ' stored in them. Then

MHT CET 2024 16th May Evening Shift Physics - Capacitor Question 15 English

A
capacitance A has high capacity.
B
capacitance B has high capacity.
C
both have same capacity.
D
capacity of $A=2$ times capacity of $B$.
4
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Air capacitor has capacitance ' $\mathrm{C}_1$ '. The space between two plates of capacitor is filled with two dielectrics as shown in figure. The new capacitance of the capacitor is ' $\mathrm{C}_2$ '. The ratio $\frac{C_1}{C_2}$ is $(d=$ distance between two plates of capacitor, $\mathrm{K}_1$ and $\mathrm{K}_2$ are dielectric constants of two dielectrics respectively)

MHT CET 2024 16th May Evening Shift Physics - Capacitor Question 16 English

A
$\mathrm{K}_1+\mathrm{K}_2$
B
$\frac{\mathrm{K}_1+\mathrm{K}_2}{\mathrm{~K}_1-\mathrm{K}_2}$
C
$\frac{2 \mathrm{~K}_1 \mathrm{~K}_2}{\mathrm{~K}_1+\mathrm{K}_2}$
D
$\frac{\mathrm{K}_1+\mathrm{K}_2}{2 \mathrm{~K}_1 \mathrm{~K}_2}$
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