MHT CET 2021 23rd September Evening Shift | Capacitor Question 30 | Physics

If the potential difference across a capacitor is increased from $$5 \mathrm{~V}$$ to $$15 \mathrm{~V}$$, then the ratio of final energy to initial energy stored in the capacitor is

$$1: 3$$

$$27: 1$$

$$3: 1$$

$$9: 1$$

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

-0

The charge on each capacitor when a voltage source os 15 V is connected in the circuit as shown, is

MHT CET 2021 23rd September Evening Shift Physics - Capacitor Question 4 English

75 $$\mu$$C

150 $$\mu$$C

30 $$\mu$$C

60 $$\mu$$C

MHT CET 2021 23th September Morning Shift

MCQ (Single Correct Answer)

-0

Two parallel plates with dielectric placed between the plates are as shown in figure. The resultant capacity of capacitor will be [A = area of plate. $$t_1, t_2$$ and $$t_3$$ are thickness of dielectric slabs, $$\mathrm{k}_1, \mathrm{k}_2$$ and $$\mathrm{k}_3$$ are dielectric constants.

MHT CET 2021 23th September Morning Shift Physics - Capacitor Question 8 English

$$\frac{A \varepsilon_0}{\left[\frac{t_1+t_2+t_3}{k_1+k_2+k_3}\right]}$$

$$ \frac{A \varepsilon_0\left(k_1 k_2 k_3\right)}{t_1 t_2 t_3} $$

$$ A \varepsilon_0\left[\frac{k_1}{t_1}+\frac{k_2}{t_2}+\frac{k_3}{t_3}\right] $$

$$ \frac{A \varepsilon_0}{\left[\frac{t_1}{k_1}+\frac{t_2}{k_2}+\frac{t_3}{k_3}\right]} $$

MHT CET 2021 22th September Evening Shift

MCQ (Single Correct Answer)

-0

In parallel plate capacitor, electric field between the plates is '$$E$$'. If the charge on the plates is '$$Q$$' then the force on each plate is

$$\frac{\mathrm{QE}^2}{2}$$

$$\mathrm{QE}^2$$

$$\frac{\mathrm{QE}}{2}$$

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