MHT CET 2026 20th April Morning Shift | Trigonometric Equations Question 1 | Mathematics

The number of common solutions of the pair of equations $2\sin^2\theta - 2\cos^2\theta + 1 = 0$ and $2\sin^2\theta + 3\sin\theta - 2 = 0$ in the interval $[0, 2\pi]$, is

$1$

$2$

$3$

$4$

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

The general solutions of the equation $\tan ^2 \theta+\sec 2 \theta=1$ are

$\mathrm{n} \pi, \mathrm{n} \pi \pm \frac{\pi}{3}, \mathrm{n} \in \mathbb{Z}$

$\mathrm{n} \pi, \mathrm{n} \pi \pm \frac{\pi}{4}, \mathrm{n} \in \mathbb{Z}$

$\quad \frac{\mathrm{n} \pi}{4}, \frac{\mathrm{n} \pi}{4} \pm \frac{\pi}{3}, \mathrm{n} \in \mathbb{Z}$

$\quad \mathrm{n} \pi, \mathrm{n} \pi \pm \frac{\pi}{6}, \mathrm{n} \in \mathbb{Z}$

MHT CET 2025 26th April Morning Shift

MCQ (Single Correct Answer)

-0

If $\tan (\pi \cos \theta)=\cot (\pi \sin \theta)$, then $\sin \left(\frac{\pi}{4}+\theta\right)=$

$\frac{1}{2}$

$\frac{1}{\sqrt{2}}$

$\frac{1}{4}$

$\frac{1}{2 \sqrt{2}}$

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