1
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The ratio of the specific heats $\frac{C_p}{C_v}=\gamma$, in terms of degrees of freedom ( n ) is

A
$\left(1+\frac{1}{n}\right)$
B
$\left(1+\frac{2}{n}\right)$
C
$\left(1+\frac{\mathrm{n}}{3}\right)$
D
$\left(1+\frac{\mathrm{n}}{2}\right)$
2
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Assuming the expression for the pressure exerted by the gas, it can be shown that pressure is

A
$\left(\frac{3}{4}\right)^{\text {th }}$ of kinetic energy per unit volume of a gas.
B
$\left(\frac{2}{3}\right)^{\text {rd }}$ of kinetic energy per unit volume of a gas.
C
$\left(\frac{1}{3}\right)^{\mathrm{rd}}$ of kinetic energy per unit volume of a gas.
D
$\left(\frac{3}{2}\right)^{\text {rd }}$ of kinetic energy per unit volume of a gas.
3
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If heat energy $\Delta \mathrm{Q}$ is supplied to an ideal diatomic gas, the increase in internal energy is $\Delta U$ and the amount of work done by the gas is $\Delta \mathrm{W}$. The ratio $\Delta \mathrm{W}: \Delta \mathrm{U}: \Delta \mathrm{Q}$ is

A
$2: 3: 5$
B
$2: 5: 7$
C
$7: 5: 9$
D
$1: 2: 5$
4
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The power radiated by a black body is P and it radiates maximum energy around the wavelength $\lambda_0$. Now the temperature of the black body is changed so that it radiates maximum energy around wavelength $\left(\frac{\lambda_0}{2}\right)$. The power radiated by it will now increase by a factor of

A
2
B
8
C
16
D
32
MHT CET Subjects
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12