1
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The mean of 100 observations is 50 and their standard deviation is 5 , then the sum of all squares of all the observations is

A
252500
B
250500
C
250000
D
255000
2
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If both mean and variance of 50 observations $$x_1, x_2, \ldots, x_{50}$$ are equal to 16 and 256 respectively, then mean of $$\left(x_1-5\right)^2,\left(x_2-5\right)^2, \ldots \ldots,\left(x_{50}-5\right)^2$$ is

A
357
B
367
C
377
D
387
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The variance of 20 observations is 5. If each observation is multiplied by 2, then variance of resulting observations is

A
5
B
10
C
4
D
20
4
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Variance of first $$2 n$$ natural numbers is

A
$$\frac{4 n^2+1}{12}$$
B
$$\frac{(2 n-1)^2}{12}$$
C
$$\frac{n^2}{3}-1$$
D
$$\frac{4 n^2-1}{12}$$
MHT CET Subjects
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