1
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+1
-0

The force acting on the electrons in hydrogen atom (Bohr's theory) is related to the principle quantum number $$n$$ as

A
$$n^{-4}$$
B
$$n^4$$
C
$$n^{-2}$$
D
$$n^2$$
2
MHT CET 2019 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the speed of an electron of hydrogen atom in the ground state is $2.2 \times 10^6 \mathrm{~m} / \mathrm{s}$, then its speed in the third excited state will be

A
$5.5 \times 10^6 \mathrm{~m} / \mathrm{s}$
B
$5.5 \times 10^5 \mathrm{~m} / \mathrm{s}$
C
$8.8 \times 10^5 \mathrm{~m} / \mathrm{s}$
D
$6.8 \times 10^6 \mathrm{~m} / \mathrm{s}$
3
MHT CET 2019 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In hydrogen emission spectrum, for any series, the principal quantum number is $n$. Corresponding maximum wavelength $\lambda$ is ( $R=$ Rydberg's constant)

A
$\frac{R(2 n+1)}{n^2(n+1)}$
B
$\frac{n^2(n+1)^2}{R(2 n+1)}$
C
$\frac{n^2(n+1)}{R(2 n+1)}$
D
$\frac{R(2 n+1)}{n^2(n+1)^2}$
4
MHT CET 2019 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the

A
second line of Balmer series
B
first line of Balmer series
C
first line of Pfund series
D
second line of Paschen series
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