MHT CET 2021 21th September Evening Shift | Atoms and Nuclei Question 100 | Physics

'$$\lambda_1$$' is the wavelength of series limit of Lyman series, '$$\lambda_2$$' is the wavelength of the first line line of Lyman series and '$$\lambda_3$$' is the series limit of the Balmer series. Then the relation between $$\lambda_1, \lambda_2$$ and $$\lambda_3$$ is

$$\frac{1}{\lambda_1}-\frac{1}{\lambda_2}=\frac{1}{\lambda_3}$$

$$\frac{1}{\lambda_1}=\frac{1}{\lambda_2}-\frac{1}{\lambda_3}$$

$$\lambda_2=\lambda_1+\lambda_3$$

$$\lambda_1=\lambda_2+\lambda_3$$

MHT CET 2021 20th September Evening Shift

MCQ (Single Correct Answer)

-0

A sample of radioactive element contains $$8 \times 10^{16}$$ active nuclei. The halt-life of the element is 15 days. The number of nuclei decayed after 60 days is

$$7.5 \times 10^{16}$$

$$2.0 \times 10^{16}$$

$$0.5 \times 10^{16}$$

$$4.0 \times 10^{16}$$

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