MHT CET 2019 2nd May Evening Shift | Atoms and Nuclei Question 91 | Physics

In Balmer series, wavelength of first line is ' $\lambda_1$ ' and in Brackett series wavelength of first line is ' $\lambda_2$ ' then $\frac{\lambda_1}{\lambda_2}$ is

0.162

0.124

0.138

0.188

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

Bohr model is applied to a particle of mass ' $m$ ' and charge ' $q$ ' is moving in a plane under the influence of a transverse magnetic field ' $B$ '. The energy of the charged particle in the $n$th level will be ( $h=$ Planck's constant)

$2 n h q B / \pi \mathrm{m}$

$n h q B / 2 \pi \mathrm{~m}$

$n h q B / 4 \pi \mathrm{~m}$

$n h q B / \pi \mathrm{m}$

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

The angle made by orbital angular momentum of electron with the direction of the orbital magnetic moment is

$120^{\circ}$

$60^{\circ}$

$180^{\circ}$

$90^{\circ}$

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

The wavelength of the first line in Balmer series in the hydrogen spectrum is ' $\lambda$ '. What is the wavelength of the second line in the same series?

$\frac{20}{27} \lambda$

$\frac{3}{16} \lambda$

$\frac{5}{36} \lambda$

$\frac{3}{4} \lambda$

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