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1
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

The frequency of revolution of an electron in the $\mathrm{n}^{\text {th }}$ orbit of hydrogen atom is

A
directly proportional to $n^2$
B
inversely proportional to $\mathrm{n}^2$
C
directly proportional to $n^3$
D
inversely proportional to $\mathrm{n}^3$
2
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
If ' $\lambda_1$ ' and ' $\lambda_2$ ' are the wavelengths of the first member of the Balmer and Paschen series, in hydrogen atom respectively, then the ratio of respective frequencies, $f_1 / f_2$, is
A
$20: 7$
B
$27: 5$
C
$50: 9$
D
$108: 7$
3
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
The ratio of the wavelength of the last line of Paschen series to that of Balmer series is
A
$\frac{9}{4}$
B
$\frac{3}{2}$
C
$\frac{2}{3}$
D
$\frac{4}{9}$
4
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In the second orbit of hydrogen atom, the energy of an electron is ' $E$ '. In the third orbit of helium atom, the energy of the electron will be (atomic number of helium $=2$)

A
$\frac{4 \mathrm{E}}{9}$
B
$\frac{4 \mathrm{E}}{3}$
C
$\frac{16 \mathrm{E}}{9}$
D
$\frac{16 \mathrm{E}}{3}$
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